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x^2=196/9
We move all terms to the left:
x^2-(196/9)=0
We add all the numbers together, and all the variables
x^2-(+196/9)=0
We get rid of parentheses
x^2-196/9=0
We multiply all the terms by the denominator
x^2*9-196=0
Wy multiply elements
9x^2-196=0
a = 9; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·9·(-196)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*9}=\frac{-84}{18} =-4+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*9}=\frac{84}{18} =4+2/3 $
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